Question

if another observation 61 is also included to the above data what woukd be the median ​

Answer 1

Answer:

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Step-by-step explanation:

Ascending order of the data =14,25,28,32,35,36,42,59,56,61

No of observations n=10 (even number)

Then there would be two numbers at the middle of the data.

Median of the data = arithmetic mean of (

2

n

)

th

and (

2

n

+1)

th

observations

= arithmetic mean of 5

th

and 6

th

observations

=

2

35+36

=35.5

Answer 2

Step-by-step explanation:

Given:

If another observation 61 is also included to the above data what would be the median?

Solution:

Ascending order of the data =14,25,28,32,35,36,42,59,56,61

No of observations n=10 (even number)

Then there would be two numbers at the middle of the data.

Median of the data = arithmetic mean of

${ \binom{n}{2} }^{th} \: and \: ({ \frac{n}{2} + 1 })^{th} \: anservations$

= arithmetic mean of 5th and 6th

observations

$= \frac{35 + 36}{2} \: = 35.5 \: ans.$