if Anshu is riding a bike with its initial speed 108km/hr. his applies the break for 10 sec and his speed decreases to 54km/hr caluelate his retadating. also find the distance covered by him.
Answers
Explanation:
Let the retardation be =a
Now u=108km/hr=108000/3600m/s=30m/s
And v=54km/hr=54000/3600m/sec=15m/s
t=10sec
We know,
V=u-at
15=30-10a
a=15/10=1.5m/s^2
Now distance =ut-(1/2)at^2
=15*10-(1/2)(1.5)(10)^2
150-75
=75m
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