If any car of speed 72km/hr need to stop after 100 m it will stop then find acceleration and time
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72km/hr = 20m/s
a = (20×20)/ (2×100)
a = -2m/s2
v=u+at
t=u/a
t=20/2
t=10s
a = (20×20)/ (2×100)
a = -2m/s2
v=u+at
t=u/a
t=20/2
t=10s
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