Question

if any one interesting in physics. Then tell me the answer. twob4kg and 2kg are sliding down an inclined plane . the acceleration of 2kg block is ? ( angle is30°)​

Answer 1

Answer:

2.6 m / s ^2

Explanation:

Given,

Force on 4 kg block sliding down the plane is:

F1=m1g(sinθ−μ1cosθ)

=4×9.8(sin30∘−0.3cos30∘)

=9.4N

Force on 2 kg block sliding down the plane is:

F2=m2g(sinθ−μ2cosθ)

=2×9.8(sin30∘−0.2cos30∘)=6.4N

Total force =F1+F2=9.4+6.4=15.8N

∴Acceleration=15.8/6

=2.6m/s^2

Note: Acceleration of block m1 is less than that of block m2 hence, both blocks will move together.

Mark me brainliest :)