Question

If any solute A dimerises in water at 1 atm pressure and the boiling point of this solution is 100.52℃ . If 2 moles of A is added to 1 lg of water and kb for water is 0.52℃/nikal,calculate the percentage association of A

Answer 1

hyee ,

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Formula for calculating i (vant haff factor) using given data is :
ΔT = i Kb m .....(1)
ΔT = elevation in boiling point = observed boiling point-original boiling point

     = 100.52° C - 100° C​
      = 0.52° C​
Kb = 0.52° C​ kg mol-1
m = moles of solute in per kg of solvent = 2 mol kg-1

Putting the values in given equation (1)

i = ∆T / Kb× m

 =0.52° / C0.52°C kg mol-1× 2 mol kg-1

= 0.5
 
 Let α be the degree of association.
At equilibrium the concentration of A would be 1-α
Concentration of dimerised form will be α/2 mole
Total number of moles in solution =  1-α + α/2
                                                  = 1-α/2

i = total moles in solution
0.5 = 1-α/2
α/2= 1/0.5
α = 1

It indicates that percentage of association of A is 100 %


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Hope it helps u !!!!!

# Nikky

Good night :))



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Answer 2

Answer:

100 percentage

Explanation:

see the attached image

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