Math, asked by udayapamu, 1 year ago

if any triangle abc is given than the value of sin(b+c\2) =

Answers

Answered by Anonymous
9

Answer:

A+B+C=180(triangle sum property of triangle)

dividing both side by 2

A/2+B+C/2=90

B+C/2=90-A/2

Sin(B+C/2)=Sin(90-A/2)

Sin (B+C/2)=Cos A/2.................(sin (90-theta)=cos theta....)

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Answered by shubhgoswami401
5

Answer:

answer is (cos a/2)

Step-by-step explanation:

i hope it is helpful for you

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