if any triangle abc is given than the value of sin(b+c\2) =
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Answered by
9
Answer:
A+B+C=180(triangle sum property of triangle)
dividing both side by 2
A/2+B+C/2=90
B+C/2=90-A/2
Sin(B+C/2)=Sin(90-A/2)
Sin (B+C/2)=Cos A/2.................(sin (90-theta)=cos theta....)
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Answered by
5
Answer:
answer is (cos a/2)
Step-by-step explanation:
i hope it is helpful for you
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