Question

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Answer 1

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Answer  and Explanation:-

ANSWER 3.):-

No. of sulphur atoms present in 1216 g SO₂

=No. of atoms of sulphur×Given mass/Molecular mass×Avogadro number

=1×1216/64×6.022×10²³==114.41×10²³

                                       =1.1441×10²⁵ atoms of Sulphur

No. of oxygen atoms present in 1216 g SO₂

=No. of atoms of oxygen×Given mass/Molecular mass×Avogadro number

=2×1216/64×6.022×10²³=114.41×10²³×2=1.1441×10²⁵×2=2.2882×10²⁵ atoms

ANSWER 4.):-

Volume of SO₂=Given mass/Molecular mass×22.4L

                       =1216/64×22.4L=19×22.4L=425.6L

ANSWER 5.):-

No. of oxygen atoms present in 48g of O₃

=No. of atoms of oxygen×Given mass/Molecular mass×Avogadro number

=3×48/48×6.022×10²³=3×1×6.022×10²³=18.066×10²³atoms

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Answer 2

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