Question

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A die is thrown 500 times. The frequency of numbers (1,2,3,4,5,6) appearing on the uppermost face are given:
Outcomes 1 2 3 4 5 6
Frequency 89 75 78 73 88 97
Find the probability of having an outcome
Number 3 on the uppermost face
39/250
3/20
89/500
None of the above

Answer 1

Answer:

$\frac{39}{250}$

Step-by-step explanation:

$probality = \frac{chances \: of \: coming}{total \: outcomes} \\ chances \: of \: coming \: of \: 3 = 78 \\ total \: outcomes = 500 \\ = > \frac{78}{500} \\ = > \frac{39}{250}$

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