Question

If anyone can solve it I will remark brainleast . I avoid unwanted answers....

Answer 1

in ΔALD,

AD² = DL² + AL²

AL² = AD² - DL²

AGAIN IN ΔALB

AB² = AL² + BL²

AB² = AD² - DL² + BL²

AB² = AD² - DL² + (BD + DL)²

AB² = AD² - DL² + BD² + DL² + 2.BD.DL

AB² = AD² + BD² + 2.BD.DL................(I)

IN ΔALC

AC² = AL² + LC²

AC² = AD² - DL² + LC²

AC² = AD² - DL² + (DC - DL)²

AC² = AD² - DL² + DC² + DL² - 2.DC.DL

AC² = AD² + DC² - 2.DC.DL

AC² = AD² + BD² - 2.BD.DL .............................(II)

ADDING EQUATION I AND II

AC² + AB² = AD² +BD² - 2.BD.DL + AD² + BD² + 2.BD.DL

AC² + AB ² = 2(AD² + BD²)

proved

Answer 2

Answer:

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Nayak nahi khalnayak hu mai