Question

If anyone can solve it ....
$\frac{3 {}^{n} \times 9 {}^{n + 1} }{3 {}^{n - 1} \times 9 {}^{n - 1} }$
Simplify the following.​

Answer 1

3^n×9^n+1/3^n-1×9^n-1

=3^n-(n-1)×9^n+1-(n-1)

=3^n-n+1×9^n+1-n+1

=3^1×9^2

=3×81

=243

Answer 2

Answer:

$\\ \frac{3 {}^{n} \times 9 {}^{n + 1} }{3 {}^{n - 1} \times 9 {}^{n - 1} } \\ =( 3 {}^{n} \times 9 {}^{n + 1} )(3 {}^{ 1 - n} \times 9 {}^{1 - n} ) \\ = 3 {}^{n + 1 - n} \times 9 {}^{n + 1 + 1 - n} \\ = 3 {}^{1} \times 9 {}^{2} = 3 \times 81 = 243 \: \: ans$

Hey! Mate Here is your solution. Thanks