Question

if anyone wire length is double(2L) & radios A/3. and present time resistance of wire 5 ohms.. so new resistance?​

Answer 1

Answer:

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Answer 2

Answer

Original Wire:

Length of wire=l

Radius=A

•°• Area of cross section of wire= πA^2

•°• Resistance= row × l / πA^2•••••{1}

New Wire:

Length=2l

Radius=A/3

Area= πA^2/9

Resistance=18*l/πA^2••••••••{2}

{1}÷{2}

Resistance of new Wire = 90ohm(Ans)

Step-by-step explanation:

I have not specified the resistivity of both the wires as both the wires are of same material so they have the same value of resistivity and hence they get cancelled on dividing (1) and (2).