Question

If AOB is a diameter of the circle having centre O and C is a point on the circle such that AC=BC. Find angle BAC.​

Answer 1

Answer:

45°

Step-by-step explanation:

given AB is the diameter of the circle with center O.C is a point on the circle such that AC is equal to BC

let's take only half of the circle in consideration

so the angle AOB is 180°

as the two lines AC and BC are equal their angles with line AB will also be equal

so angle CAB =angle CBA

hence this is a 45° 45° 90° triangle

CAB=CBA=45°

AND ACB=90°