If ap and pb are tangents and apb is 40 degree find aqb
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Step-by-step explanation:
Join OB.
We know that the radius and tangent are perpendicular at their point of contact.
∴ ∠OBP=∠OAP=90o
Now, In a quadrilateral AOBP
⇒ ∠AOB+∠OBP+∠APB+∠OAP=360o [ Sum of four angles of a quadrilateral is 360o. ]
⇒ ∠AOB+90o+40o+90o=360o
⇒ 220o+∠AOB=360o
⇒ ∠AOB=140o.
Since OA and OB are the radius of a circle then, △AOB is an isosceles triangle.
⇒ ∠AOB+∠OAB+∠OBA=180o
⇒ 140o+2∠OAB=180o [ Since, ∠OAB=∠OBA ]
⇒ 2∠OAB=40o
∴ ∠OAB=20o
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