Question

If AP=CP then prove that BP is angle bisector of angle ABC

Answer 1

Answer:

angle ABP = CBP

Step-by-step explanation:

in triangle APB and triangle CPB

AP=CP (given)

BP=BP (common)

angle APB = CPB = 90 degree

therefore triangle APB congruent to CPB (SAS)

angle ABP = CBP (CPCT)

so BP is the angle bisector of angle ABC