Math, asked by pihuprachi212, 10 months ago

if AP is n-1, 4n-1,5n-1.find the value of n.

Answers

Answered by aakashaneja1993
1

Answer:

(n-1)-(4n-1)=(4n-1)-(5n-1)

(n-1)+(5n-1)=(4n-1)+(4n-1)

n-1+5n-1=4n-1+4n-1

6n-2=8n-2

-2n=0n=0

Answered by Anonymous
0

Answer:

a= n-1

d=4n-1-(n-1

d=4n-1-n+1

d=3n

an=5n-1

a3=a+2d

5n-1=n-1+2 (3n)

5n-1=n-1+6n

5n-7n=-2

-2n= -2

n=1

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