if AP is n-1, 4n-1,5n-1.find the value of n.
Answers
Answered by
1
Answer:
(n-1)-(4n-1)=(4n-1)-(5n-1)
(n-1)+(5n-1)=(4n-1)+(4n-1)
n-1+5n-1=4n-1+4n-1
6n-2=8n-2
-2n=0n=0
Answered by
0
Answer:
a= n-1
d=4n-1-(n-1
d=4n-1-n+1
d=3n
an=5n-1
a3=a+2d
5n-1=n-1+2 (3n)
5n-1=n-1+6n
5n-7n=-2
-2n= -2
n=1
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