If apha and beta are the zeroes on the quadratic polynomial f(x)=px2+qx+r then find the value of 1/p apha+q +1/pbeta+q o==[]::::::::::::::::>
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f(x)=px2 +qx +r;
sum of the roots= alpha+Beta =(-q/p);
product of the roots =alpha*beta= r/p;
Put these values in the expression
1/ (p.alpha+q) + 1/ (p.beta+q)
On solving you will get = q/(pr)
Thanks.
PL mark me as brainlest
f(x)=px2 +qx +r;
sum of the roots= alpha+Beta =(-q/p);
product of the roots =alpha*beta= r/p;
Put these values in the expression
1/ (p.alpha+q) + 1/ (p.beta+q)
On solving you will get = q/(pr)
Thanks.
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