if apha and beta are the zeros of x2+5x+6 then find the value of alpha-1+beta-1
Shreya4:
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Answered by
3
Since x^2+5x+6 is a quadratic Equation. hence the sum of roots/zeros of the equation is alpha +beta =-b/a = -coefficient of x/coefficient of x^2= -5 .Since we have to find alpha +beta -2=-5-2 =-7
So the answer is -7
So the answer is -7
NOW WE have alpha +beta /alpha *beta = -5/6..numerator =sum of roots/product of roots
Answered by
3
x^2+5x+6=0
x^2+2x+3x+6=0
x(x+2)+3(x+2)=0
(x+3)(x+2)=0
so the roots are -3 and -2
as the question is alpha-1+beta-1
-3-1-2-1
-7
I hope this will help u ;)
x^2+2x+3x+6=0
x(x+2)+3(x+2)=0
(x+3)(x+2)=0
so the roots are -3 and -2
as the question is alpha-1+beta-1
-3-1-2-1
-7
I hope this will help u ;)
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