if apha and beta are zeroes of the polynomial x^2-p(x+1)+c such that (apha+1)(beta+1)=0, then find the value of c.
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alpha+ beta=+p/1
B/Q
alpha + beta =-2
-2=p/1
p=-2
alpa*beta =c/1
c=alpha* beta
c=-alpha*(2+alpha)
c=2alpha + alphasquare
B/Q
alpha + beta =-2
-2=p/1
p=-2
alpa*beta =c/1
c=alpha* beta
c=-alpha*(2+alpha)
c=2alpha + alphasquare
arup37:
I think my answer isnot correct plz ask your teacher this question
thank you for trying i was also thinking so that it isn't correct.
(alpha+1)(beta+1)=0.
alpha+beta+alphabeya=-1
from the equation we get
alpha+beta=p/1
alphabeta=c-p/1
p+c-p=-1
c=-1
This is your answer
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