if aplha and beta are roots of equation x^2-x-1 =0 then alpha^4+ beta^4=?
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Step-by-step explanation:
x² - x - 1 = 0
a = 1, b = -1, c = -1
Sum of roots = α + β = -b/a = -(-1)/1 = 1
Product of roots = αβ = c/a = -1/1 = -1
//Also we know that a² + b² = (a + b)² - 2ab
α⁴ + β⁴ = (α²)² + (β²)² = (α² + β²)² - 2α²β²
= [(α + β)² - 2αβ]² - 2(αβ)²
= [(1)² - 2(-1)]² - 2(-1)²
= (1 + 2)² - 2
= 9 - 2
= 7.
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