Math, asked by UGireesh, 10 months ago

if AR=36,CM=78,GP=224,ES=___.Then ES=__​

Answers

Answered by SUBRATA4322
5

Answer:

AR=36

A=1,R=18

(1+1)×18=36

CM=78

C=3,M=13

(3+3)×13=78

GP=224

G=7,P=16

(7+7)×16=224

ES=190

E=5,S=19

(5+5)×19=190

Answered by Anonymous
0

Given:

AR=36, CM=78, GP=224

To find:

The value of ES

Solution:

The numerical value of ES= 190.

We can find the value by following the given process-

We know that the value of the given combinations of letters is derived in a particular way.

Here, each combination is formed by taking the positions of each of the given letters.

To obtain the numerical value, we need to multiply the position of the first letter by 2 and then multiply it with the position of the second letter.

In AR, A's position is 1, and R's position is 18 in the alphabet.

So, the value of AR=(1×2)×18=36

C's position is 3rd and M's is 13.

Similarly, the value of CM=(3×2)×13=78

G's position is 7 and P's is 16.

The value of GP=(7×2)×16=224

Now, for ES, E's position is 5, and S's is 19.

The value of ES=(5×2)×19=190

ES=190

Therefore, the numerical value of ES is 190.

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