Math, asked by samruddhiy12, 3 months ago

If arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 150°, then m(arc AYB) = ?​

Answers

Answered by pulakmath007
10

SOLUTION

GIVEN

arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 150°

TO DETERMINE

m(arc AYB)

EVALUATION

Here it is given that arc AXB and arc AYB are corresponding arcs

∴ AXBY is a cyclic quadrilateral

We know that in a cyclic quadrilateral , the sum of the opposite angles is 180°

∴ m(arc AXB) + m(arc AYB) = 180°

⇒ 150° + m(arc AYB) = 180°

⇒ m(arc AYB) = 180° - 150°

⇒ m(arc AYB) = 30°

FINAL ANSWER

m(arc AYB) = 30°

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