If arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 150°, then m(arc AYB) = ?
Answers
SOLUTION
GIVEN
arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 150°
TO DETERMINE
m(arc AYB)
EVALUATION
Here it is given that arc AXB and arc AYB are corresponding arcs
∴ AXBY is a cyclic quadrilateral
We know that in a cyclic quadrilateral , the sum of the opposite angles is 180°
∴ m(arc AXB) + m(arc AYB) = 180°
⇒ 150° + m(arc AYB) = 180°
⇒ m(arc AYB) = 180° - 150°
⇒ m(arc AYB) = 30°
FINAL ANSWER
m(arc AYB) = 30°
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