Question

if Arccos x >Arcsinx ,then
a.0 less than equal to x ,less than 1/√2
b. -1 less than equal to x ,less than 1/√2
c.0 less than x ,less than 1/√2
Here ,which option is right, a or b or c??
Answer it with reason or explanation.
I will surely mark it as brainliest.

Answer 1

According to me, it's answer should be
$a \: \: 0 \leqslant x < 1 \div \sqrt{2}$
the reason is as below
assume
$arc = l$
so if
$l \cos(x) > l \sin(x)$
cancelling L from both sides we get
$\cos(x) > \sin(x)$
and for that condition to be true your x has to be in
$0 \leqslant x < 45 \: or \: \binom{\pi}{4}$
but as that is not in options
REAL ANSWER ACCORDING TO ME SHOULD BE NONE OF THIS
but as it is not in options so I tried to check their cosine values
and that is matching with first option thus I am telling that your answer could be A