Question

If α , β are roots of the equation 9x2+6x+1=0 then find the equation whose roots are reciprocal to the given roots.

Answer 1

Answer:x^2+6x+9=0

Step-by-step explanation:

9x^2+6x+1=0

(3x)^2+2(3x)(1)+(1)^2=0

(3x+1)^2=0

3x+1=0

x=-1/3

Reciprocal of -1/3 is -3

hence -3 and-3 are the roots of required equation

required equation:

(x-(-3))(x-(-3))=0

(x+3)^2=0

x^2+6x+9=0