Question

if ∝,β are the roots of px²-px+q=0 then ∝/β+β/∝

Answer 1

Step-by-step explanation:

$\alpha +\beta = -(-p)/p = 1\\\alpha \beta =q/p\\\\frac{\alpha }{\beta }+\frac{\beta }{\alpha } = \frac{\alpha^{2} + \beta ^{2}}{\alpha \beta } = \frac{( \alpha +\beta )^{2} - 2\alpha \beta }{\alpha \beta } = \frac{1^{2} - 2\frac{p}{q} }{\frac{p}{q} } = \frac{q(q-2p)}{pq} =\frac{q-2p}{pq}$