If α,β are the roots of x^2+x+3=0 then 5α +α^2 +3α + 5β+3 =
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Sum of Zeroes is a+B=-1/1
a+B=-1
a=-B-1..(1)
Product of Zeroes is a×B=3/1=3
B(-B-1)=3
-B^2-B=3
-B-1=3
B=-4
replace the value in equation 1
a=-4-1
a=-5
Replace this value a and B in the polynomial
Now, u solve yourself by putting the a and B value
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