Question

If α,β are the roots of x²-x+1=0 then 1÷α³+1÷β³=?
1)2
2)-2
3)1
4)0​

Answer 1

Alpha+beta=-b/a

Alpha+beta=-(-1)/1

Alpha+beta=1

alpha×beta=c/a

Alpha×beta=1/1

Alpha×beta=1

1÷Alpha³+1÷beta³

(aloha³+beta³)÷alpha³×beta³

(alpha+beta)(alpha²+alphabeta+beta²)÷1³×1³ (:'a³+b³=(a+b)(a²+ab+b²) )

1×(Alpha²+beta²+1) (identify a²+b²=(a+b)²-2ab)

1×(alpha+beta)²-2alpha Beta

1×2-2

Ans. is 4th d(0)

Answer 2

Thanks for asking this question

your sincerely sathvik(HV SNIPER)