Question

if α+β are the zeroes of p(x)=ax^2+bx+c. Then find α^3+β^3=?​

Answer 1

Step-by-step explanation:

α+β= -b/a

βα=c/a

p(x)=ax²+bx+c

=>α+β= -b/a  ------------1

βα=c/a

(a+b)³=a³+b³+3ab(a+b)

from 1

(α+β)³=(-b/a)³

α³+β³+3αβ(α+β)= -b³/a³

α³+β³+3[c/a(-b/a)]= -b³/a³

α³+β³-3bc/a²= -b³/a³

α³+β= -b³/a³+3bc/a²

       = -b³+3abc/a³

Answer 2

Answer:

=-b 3

Step-by-step explanation:

+3abc/a3

hope it helps you