Math, asked by rishabpanday3443, 1 year ago

if α,β are the zeroes of quadratic polynomial f(x)=xsquare-x-4 find the value of 1/α+1/β-αβ​

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Answered by yogeshkumar1605
1

Step-by-step explanation:

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Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
0

\huge\sf\pink{Answer}

☞ Your Answer is 15/4

\rule{110}1

\huge\sf\blue{Given}

☆ α and β are the zeros of x²-x-4

\rule{110}1

\huge\sf\gray{To \:Find}

✭ 1/α+1/β-αβ

\rule{110}1

\huge\sf\purple{Steps}

Given polynomial ;

f(x) = x² - x - 4

On comparing the given equation with ax² + bx + c = 0, we get -

◕ a = 1

◕ b = - 1

◕ c = - 4

\sf Sum \ of \ zeroes = - \dfrac{b}{a}

➢ α + β = - (-1)

➢ α + β = 1

\sf Product \ of \ zeroes =\dfrac{c}{a}

➝ αβ = - 4

Now,

\sf\frac{1}{ \alpha } + \frac{1}{ \beta } - \alpha \beta \\ \\ \sf\dashrightarrow \frac{ \alpha + \beta - ( \alpha \beta ) {}^{2} }{ \alpha \beta } \\ \\ \sf\dashrightarrow \frac{1 - ( - 4) {}^{2} }{ - 4} \\ \\ \sf\dashrightarrow \frac{1 - 16}{ - 4} \\ \\ \sf \dashrightarrow \frac{ - 15}{ - 4}

\rule{170}3

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