Question

If α, β, γ are the zeroes of the cubic polynomial ax³ + bx² + cx + d then α + β + γ is equal ​

Answer 1

Answer:

αβ+βγ+αγ=$\frac{c}{a}$

Step-by-step explanation:

Fundamental facts:  

If α,β,γ  are the roots of cubic equation  $ax^3+bx^2 +cx + d =0$

then,  α+β+γ = $-\frac{b}{a}$

αβ+βγ+γα= $\frac{c}{a}$

and αβγ = $-\frac{d}{a}$

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Answer 2

Answer:

$- \frac{ b}{a}$

Step-by-step explanation:

The relation between zeros and coefficients of a Cubic polynomial is given by:

$\alpha + \beta + \gamma = \: - \frac{coefficient \: of \: x {}^{2} }{coefficient \: of \: x {}^{3} }$

So, implying this rule in the above given polynomial.

We have:

$\alpha+\beta+\gamma = - \frac{b}{a}$

Hope you get this!!