If (α, β, γ) are the zeroes of the polynomial 2x^3+x^2-13x+6, then αβγ=?
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Step-by-step explanation:
α,βandγarethe
zerosofthepolynomial
2x
3
+x
2
−13x+6
/* Compare above polynomial by ax³+bx²+cx+d ,we get
a = 2 , b = 1 , c = -13 , d = 6a=2,b=1,c=−13,d=6
\begin{lgathered}\alpha \cdot \beta \cdot \gamma \\= \frac{-d}{a}\\= \frac{-6}{2} \\= \green {-3}\end{lgathered}
α⋅β⋅γ
=
a
−d
=
2
−6
=−3
Therefore.,
\begin{lgathered}\alpha \cdot \beta \cdot \gamma \\= \green {-3}\end{lgathered}
α⋅β⋅γ
=−3
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