Question

If α,β are the zeroes of the polynomial
2x2-7x +k satisfying the condition
α2+β2+αβ= 67/4, then find the value of k
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Dont Spam # Quality Answer Need...
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No Need Copied Answer
Spammer will be report​

Answer 1

Given :-

2x² - 7x + k

α² + β² + αβ = 67/4

Solution :-

We know that

Sum of zeroes = -b/a

We have

b = -7

a = 2

Sum of zeroes = -(-7)/2

Sum of zeroes = 7/2

Product of zeroes = c/a

c = k

a = 2

Product of zeroes = k/2

α² + β² + αβ = 67/4

α² + β² + (2αβ - αβ) = 67/4

Taking 2 as common

(α + β)² - αβ = 67/4

Putting all values

(7/2)² - (k/2) = 67/4

(7²/2²) - k/2 = 67/4

49/4 - k/2 = 67/4

49 - 2k/4 = 67/4

49 - 2k = 67

-2k = 67 - 49

-2k = 18

k = 18/-2

k = -18/2

k = -9/1

k = -9

Answer 2

If α,β are the zeroes of the polynomial

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the condition

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k────────────────

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k────────────────Dont Spam # Quality Answer Need...

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k────────────────Dont Spam # Quality Answer Need...─────────────

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k────────────────Dont Spam # Quality Answer Need...─────────────No Need Copied Answer

If α,β are the zeroes of the polynomial2x2-7x +k satisfying the conditionα2+β2+αβ= 67/4, then find the value of k────────────────Dont Spam # Quality Answer Need...─────────────No Need Copied AnswerSpammer will be report