Math, asked by akshat200659, 8 months ago

If α , β are the zeroes of the polynomial p(x)=4x2 + 4x +1 , then the sum of their reciprocals is :​

Answers

Answered by shekhawatonly4u
1

Answer:

-4 is the right answer mark as brainliest

Answered by nehneethak
2

Answer:

α and β are the zeroes of 4x² + 4x +1 

a = 4 

b  =4 

c = 1

sum of zeroes = -b/a

α + β = -b/a

α+ β = -4 /4 

α + β = -1 ........................(i)

product of zeroes  = c/a

αβ = c/a

αβ = 1/4 ................(ii)

zeroes of polynomial are 2α and 2β

so 

sum of zeroes = 

2α + 2 β

2(α+β)         from (i)

2(-1)

-2

product of zeroes 

(2α)(2β)

4αβ

4 (1/4)                  from (ii)

polynomial = 

x ² - ( sum of zeroes )x + product of zeroes

x² - (-2)x +1

x² +2 x+1

HOPE IT HELPS U

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