Question

If ⋉ are the zeroes of the polynomial p(x) = x 2 – x+1, then 1 ⋉ + 1 = (a) 1 (b) -1 (c) 0 (d) none of these

Answer 1

Answer:

-1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Solution : By taking L.C.M of dinominators

→ 1/α + 1/β = (α + β)/αβ

Since we know that,

→ α + β = - Coefficient of x/Coefficient of x²

→ α + β = - 1/1 = - 1

→ αβ = Constant Term/Coefficient of x²

→ αβ = 1/1 = 1

∴ (α + β)/αβ = - 1/1

→ - 1

Answer : - 1