If α, β are the zeroes of the quadratic polynomial x
2
+3x+6, Find the value of
(α/β+β/α)
Answers
Answered by
6
Answer :
-½
Explanation :
Given polynomial,
⇒x² + 3x + 6
On comparing with ax² + bx + c we get,
- a = 1
- b = 3
- c = 6
Then,
- α + β = -b/a = -3
- αβ = c/a = 6
Finding (α/β + β/α)
⇒ α² + β²/αβ
⇒ (α + β)² - 2αβ/αβ
On substituting the values,
⇒ (-3)² - 2(6)/6
⇒ 9 - 12/6
⇒ -3/6
⇒ -½
Required answer : -½
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