Question

If are the zeros of () =
2 − 2 + 3 + = , then find the value of p .

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

2x2−5x−3=0

2x2−6x+x−3=0

(x−3)(2x+1)=0

x=3,−21

Now,

Zeroes of the polynomial x2−px+q are double in values to the zeroes of polynomial 2x2−5x−3.

Therefore,

Zeroes of polynomial x2−px+q will be- 6,−1

Therefore,

Sum of roots =a−b

6+(−1)=−(−p)

⇒p=5

Product of root =ac

6×−1=q

⇒q=−6

Hence the values of p and q are 5 and −6 respectively.

Answer 2

Step-by-step explanation:

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q(x)=2x2-3x+p

q(3)=2×(3)^2-3×3+p

0 =2×9-9+p

0 =18-9+p

0 =9+p

p =-9

q(x)=2x2-3x+p

q(x)=2x2-3x-9

=2x2-(6-3)x-9

=2x2-6x+3x-9

=2x(x-3)+3(x-3)

=(2x+3)(x-3)

x=-3/2,3