If α , β are the zeros of 2y2+7y+5 write the value of α+ β +α β
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15
Hey,
Here is your answer,
2y^2 + 7y +5=0
Sum of zeroes= -b/a
Alpha + beta = -7/2
Product of zeroes = c/a
Alpha x beta = 5/2
Alpha + beta + alpha x beta = (-7/2)+(5/2)
= -2/2
= -1
Hope it helps you!
Here is your answer,
2y^2 + 7y +5=0
Sum of zeroes= -b/a
Alpha + beta = -7/2
Product of zeroes = c/a
Alpha x beta = 5/2
Alpha + beta + alpha x beta = (-7/2)+(5/2)
= -2/2
= -1
Hope it helps you!
Answered by
0
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