Question

 if α ,β are the zeros of kx²-2x+3k such that α + β = α β then k=? 


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Answer 1

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{The \ value \ of \ k \ is \frac{2}{3}.}$

$\bold\blue{Explanation}$

$\bold{The \ given \ quadratic \ polynomial \ is}$

$\bold{k^{2}-2x+3k}$

$\bold{Here, \ a=k, \ b=-2 \ and \ c=3k}$

$\bold{We \ know \ that,}$

$\bold{\alpha+\beta=\frac{-b}{a}}$

$\bold{\alpha×\beta=\frac{c}{a}}$

$\bold\orange{Given:}$

$\bold{=>The \ given \ quadratic \ polynomial \ is}$

$\bold{k^{2}-2x+3k}$

$\bold{=>\alpha \ and \ beta \ are \ zeroes.}$

$\bold{=>\alpha+\beta=\alpha×\beta}$

$\bold\pink{To \ find:}$

$\bold{=>The \ value \ of \ k.}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{The \ given \ quadratic \ polynomial \ is}$

$\bold{k^{2}-2x+3k}$

$\bold{\alpha+\beta=\alpha×\beta}$

$\bold{\frac{-b}{a}=\frac{c}{a}}$

$\bold{\frac{-(-2)}{k}=\frac{3k}{k}}$

$\bold{k=\frac{2}{3}}$

$\bold{Therefore,}$

$\bold\purple{The \ value \ of \ k \ is \frac{2}{3}.}$

Answer 2

Answer:

Sorry I have not solved this chapter