If α,β are the zeros of the polynomial, x^2-px +36 and α^2 + β^2 = 9, then what is the value of p? *
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Answer:
Here a+B=p and aB=36
Now (a+B)^2=a^2+B^2+2aB
P^2=9+2×36
P^2=81
P=9,-9
Hence P=9,-9
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