If α,β are the zeros of the polynomial, x^2-px +36 and α^2 + β^2 = 9, then what is the value of p? *
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Answer:
9
Step-by-step explanation:
Here a+b = p and ab = 36
Now (a+b)² = a²+b²+2ab
p² = 9 + (2×36) ( °.° a²+b² = 9 )
p² = 81
p = +9 or -9
Hence p = 9 ( -9 is rejected)
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