Math, asked by harkamal1320, 1 year ago

If α β γ are zeroes of polynomial ax^3+ bx^2+ cx + d, find 1/αβ+1/βγ+1/αγ

Answers

Answered by Anonymous
2

Solution : On solving 1/α + 1/β + 1/γ we get,

• (αβ + βγ + αγ)/αβγ

Since we know that,

αβ + βγ + αγ = c/a

αβγ = - d/a

Therefore,

(αβ + βγ + αγ)/αβγ = c/a × a/(- d)

= - c/d

Answer : - c/d

______________________________

Explaination :-

• αβ + βγ + γα = Coefficient of x/Coefficient of x³

• αβγ = - Constant Term/Coefficient of x³


Anonymous: I think this will help you a lot
bhaskar169: your anser is wrong
Anonymous: I know I just try
Answered by bhaskar169
0

Step-by-step explanation:

The solution is given in the snap. Refer to the snap.

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