If α β γ are zeroes of polynomial ax^3+ bx^2+ cx + d, find 1/αβ+1/βγ+1/αγ
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Solution : On solving 1/α + 1/β + 1/γ we get,
• (αβ + βγ + αγ)/αβγ
Since we know that,
αβ + βγ + αγ = c/a
αβγ = - d/a
Therefore,
(αβ + βγ + αγ)/αβγ = c/a × a/(- d)
= - c/d
Answer : - c/d
______________________________
Explaination :-
• αβ + βγ + γα = Coefficient of x/Coefficient of x³
• αβγ = - Constant Term/Coefficient of x³
Anonymous:
I think this will help you a lot
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