Question

If α, β are zeroes of polynomial p(x) = 3x2 – 5x + 7, then find the value of

α2+ β2

​

Answer 1

Step-by-step explanation:

$\alpha + \beta = \frac{5}{3} \\ \alpha \beta = \frac{7}{3}$

Now,

α^2 + β^2 = (α+β)^2 - 2αβ = (5/3)^2 - 2×7/3

=> α^2 + β^2 = -17/9

Answer 2

Answer:

-17/9

Step-by-step explanation:

α2+ β2 = (α+β)^2-2αβ   ---eq 1

α+β=  -b/a=-(-5/3)=5/3

αβ=c/a=7/3

2αβ=14/3

substituting values in eqn 1

α2+ β2=25/9-42/9=    -17/9