Math, asked by ashikdavid, 1 year ago

If α, β, are zeroes of polynomial p(x) = 5x2 + 5x + 1 then find the value of
(i) α2 + β2
(ii) α -1 + β-1

Answers

Answered by MarkAsBrainliest
399
\textbf{Answer :}

The given polynomial is

p (x) = 5x² + 5x + 1

Since α and β are the zeroes of p (x),

α + β = - 5/5

⇒ α + β = - 1 ...(1)

and

αβ = 1/5 ...(2)

(i) Now, α² + β²

= (α + β)² - 2αβ

= (- 1)² - 2 (1/5)

= 1 - 2/5

= (5 - 2)/5

= 3/5

(ii) Now, α^(- 1) + β^(- 1)

= 1/α + 1/β

= (β + α)/(αβ)

= (- 1)/(1/5)

= - 5

#\textbf{MarkAsBrainliest}
Answered by fadilep123
75

Answer:

The given polynomial is

p (x) = 5x² + 5x + 1

Since α and β are the zeroes of p (x),

α + β = - 5/5

⇒ α + β = - 1 ...(1)

and

αβ = 1/5 ...(2)

(i) Now, α² + β²

= (α + β)² - 2αβ

= (- 1)² - 2 (1/5)

= 1 - 2/5

= (5 - 2)/5

= 3/5

(ii) Now, α^(- 1) + β^(- 1)

= 1/α + 1/β

= (β + α)/(αβ)

= (- 1)/(1/5)

= - 5

PLS MARK AS BRAINLIEST....

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