If α, β, are zeroes of polynomial p(x) = 5x2 + 5x + 1 then find the value of
(i) α2 + β2
(ii) α -1 + β-1
Answers
Answered by
399
The given polynomial is
p (x) = 5x² + 5x + 1
Since α and β are the zeroes of p (x),
α + β = - 5/5
⇒ α + β = - 1 ...(1)
and
αβ = 1/5 ...(2)
(i) Now, α² + β²
= (α + β)² - 2αβ
= (- 1)² - 2 (1/5)
= 1 - 2/5
= (5 - 2)/5
= 3/5
(ii) Now, α^(- 1) + β^(- 1)
= 1/α + 1/β
= (β + α)/(αβ)
= (- 1)/(1/5)
= - 5
#
Answered by
75
Answer:
The given polynomial is
p (x) = 5x² + 5x + 1
Since α and β are the zeroes of p (x),
α + β = - 5/5
⇒ α + β = - 1 ...(1)
and
αβ = 1/5 ...(2)
(i) Now, α² + β²
= (α + β)² - 2αβ
= (- 1)² - 2 (1/5)
= 1 - 2/5
= (5 - 2)/5
= 3/5
(ii) Now, α^(- 1) + β^(- 1)
= 1/α + 1/β
= (β + α)/(αβ)
= (- 1)/(1/5)
= - 5
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