Question

If α, β are zeroes of the polynomial x^2
-2x-8, then form a quadratic polynomial whose zeroes are

2α and 2β

Answer 1

hope it will help you

Answer 2

$\alpha + \beta = - b \div a \\ \: \alpha \times \beta = c \div a$
so
putting formula we get
$\alpha + \beta = - b \div a = - ( - 2) \div 1 \\ 2 \div 1 = 2 \\ \alpha \times \beta = c \div a = - 8 \div 1 = - 8$ so 2alpha = 2×2=4 and 2beta= 2×-8=-16
so equation is x^2+6x-16