Question

if α,β are zeros of x^2+7x+10 then αβ=​

Answer 1

we know that

for equation

$a {x}^{2} + bx + c = 0$

product of zeroes of equation=

constant term / coffcient of X ^2

then ,

$\alpha \beta = 10$

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Answer 2

Answer:

$\large{\underline{\boxed{\sf \alpha \beta = 10}}}$

Step-by-step explanation:

Given that ;

α and β are the zeroes of the quadratic polynomial x² + 7x + 10.

On comparing the given equation with ax² + bx + c. We get -

• a = 1
• b = 7
• c = 10

Product of zeroes = $\bf \dfrac{c}{a}$

⇒ α * β = $\sf \dfrac{10}{1}$

⇒ αβ = 10

Hence, the answer is (10).

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$\large{\underline{\underline{\mathfrak{\heartsuit \: Extra \: Information: \: \heartsuit}}}}$

For a quadratic polynomial, ax² + bx + c the zeroes are α and β. Here -

• α + β = -b/a
• αβ = c/a