If area.Is36 perimeter 30 so what is length and width
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Answered by
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area=36
so, let l be (x)
w(breadth) be (x)
so
area=l*b
36=x*x
36=x2(square)
x=36(2) square
x=6cm
so l=6cm and b=6cm
perimeter=2(l+b)
let l be x
let w(Breadth) be x
so
30=2(l+b)
30=2(x+x)
30=2(2x)
30=4x
x=30/4
x=7.5cm
dorri:
why did you took length & width common??
Answered by
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Area
36=l×b
36/b = l
Perimeter
30= 2(l+b)
30=2(36/b+b) [putting value of l as 36/b]
15b= 36 + b²
b²-15b+36
Splitting the Middle term
b²-12b-3b+36
b(b-12) -3(b-12)
(b-12) & (b-3)
b= 12 & 3
So, length=12, breadth=3(as we know, length is greater than breadth)
You can also verify it.
Hope it helps you :)
36=l×b
36/b = l
Perimeter
30= 2(l+b)
30=2(36/b+b) [putting value of l as 36/b]
15b= 36 + b²
b²-15b+36
Splitting the Middle term
b²-12b-3b+36
b(b-12) -3(b-12)
(b-12) & (b-3)
b= 12 & 3
So, length=12, breadth=3(as we know, length is greater than breadth)
You can also verify it.
Hope it helps you :)
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