Question

If area of a parallelogram is 29.6sq.cm and its base is 8cm, then find its height
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Answer 1

Given :

• Area of parallelogram = 29.6 cm²

• Base of parallelogram = 8 cm

To Find :

• Height of the parallelogram

Solution :

$\boxed{ \boxed{ \large \sf Area_{parallelogram} =Base \times Height }} \\ \\ \implies \sf29.6 = 8 \times h \\ \\\implies \sf h = \frac{29.6}{8} \\ \\ \implies \boxed{ \boxed { \sf h = 3.7 \: cm}}$

$\large \underline{ \sf Height \: of \: parallelogram \: is \: 3.7 \: cm}$

Parallelogram :

• Perimeter = 2 x (sum of lengths of adjacent sides)

• Number of vertices = 4

• Number of edges = 4

• Properties = Convex polygon

• Type = Quadrilateral

• Line of symmetry = 0

Answer 2

✯✯ QUESTION ✯✯

If area of a parallelogram is 29.6sq.cm and its base is 8cm, then find its height..

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✰✰ ANSWER ✰✰

$⇢Area\:of\:Parallelogram={29.6cm}^{2}$

$⇢Base\:of\:Parallelogram=8cm$

$⇢Height=?$

➜Now ,

☛$\small{\boxed{\bold{\bold{\green{\sf{Area\:of\:Parallelogram=Base×Height}}}}}}$

$⇢29.6=8×h$

$⇢\dfrac{29.6}{8}=h$

☛$\large{\boxed{\boxed{\bold{\purple{\sf{Height={3.7cm}^{2}}}}}}}$