If area of a rectangle with length (a - b)
breadth (2atb) is the same as the
algebraic expression Kab+ 202-62 find K.
Solve - Ascotsectangle = kab+202-62
(a - b)x(2a+b) = Kabt 202-6²
= 202 + ab-2ab-b² - Kabt 2012 - 6²
- 2012 - ab-b² = kab+ 20²-6²
on comparing
=
we get
K = - I
= -1
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