Question

If area of a rhombus is 102 sq dm and one of its diagonal is 12 dm , find the meausrement of other diagonal. *​

Answer 1

$\frac{1}{2} \times d {}^{1} \times d {}^{2} = rhombus \\ = > \frac{1}{2} \times 12 \times x = 102 \\ = > 6x = 102 \\ = > x = 17 \: dm.$

Answer 2

Answer:

let b be the breadth

Area of rectangle = 102

b = 102

b = 102/17

b = 6

Perimeter of rectangle = 2 ( l+b)

=> 2 * ( 17 + 6)

=> 2×23

=> 46 cm

Step-by-step explanation: