Question

if area of a trapezium is 49 cm² , parallel sides are 4cm and 14 cm , then height is ​

Answer 1

Answer:

Distance between parallel sides = height of trapezium

Area of trapezium =

2

1

(sum of parallel sides) × height

441=

2

1

(x+28)×18

⇒x+28=49⇒x=21cm

Answer 2

Answer:

Height is $=5\frac{4}{9} cm$

Step-by-step explanation:

Area of a trapezium = $\frac{1}{2} (a + b) . h$ where a and b are the lengths of the parallel sides and h is the height.

According to the problem:

49 = $\frac{1}{2} (4 + 14) . h$ = 9h

∴ h $=\frac{49}{9} = cm = 5\frac{4}{9} cm$