Question

if area of an equilateral triangle is 16√3 cm² then find the height of the triangle​

Answer 1

Answer:

$area \: of \: equilateral \: triangle = \frac{ \sqrt{3} {a}^{2} }{4} \\ \frac{ \sqrt{3} {a}^{2} }{4} = 16 \sqrt{3} \\ {a}^{2} = 16 \times 4 \\ a = \sqrt{4 \times 4 \times 2 \times 2} \\ a = 8cm \\ height \: of \: eqilateral \: triangle = \frac{ \sqrt{3}a }{2} = 4 \sqrt{3} cm$

Hope it helps you....

Answer 2

ANSWER-

We know that,

area of an equilateral triangle = s² × √3/4

16√3. = s² × √3/4

s² = 16×4

s = √64 = 8 cm

we know that,

area of a triangle = 1/2 × bh

16√3 = 1/2 × 8h

4√3 = h

Therefore the height of the triangle is 4√3 cm.

cheers!!